Find the acceleration of the block of mass M = 5.06 kg in the figure below. (Take m = 4.24 kg.)

If you pasted a diagram, that does not work here.

//d2vlcm61l7u1fs.cloudfront.

net/media%2Ff38%2Ff385e045-5c9f-4f53-8ded-aa29a4d1d55c%2FphpOMgUlO.png

This the rightlink //d2vlcm61l7u1fs.cloudfront.

net/media%2Ff38%2Ff385e045-5c9f-4f53-8ded-aa29a4d1d55c%2FphpOMgUlO.png

Say TL = tension in left string

Say TR = tension in right string
a = acceleration of all to right

On the middle mass
F = TR - TL - 0.10*2*g = 2 a
TR = 5.06 (g-a)
TL = 4.24 (g+a)
so
5.06(g-a)-4.24(g+a) =2 a + 0.2g
0.82 g - 9.3 a = 2 a + 0.2 g
11.3 a = 0.62 g
a = .055 g
if g = 9.81 m/s^2
then
a = 0.538 m/s^2

No problem, was able to get there from first link.

you are so coolDamon

where did you get 0.2g from?

How 5.06(g-a)become 0.82 g and 4.24(g+a)become 9.3

where did 0.62g come from?

I don't get it can you do it in number form?