I am looking factoring with the distributive property.
4m^2 + 4mp + 3mp + 3p^2
You have a few options...
If you group the terms then you will have a common factor at the end.
(4m^2 + 4mp)+ (3mp + 3p^2)
This should get you started : )
Or... just put your 4mp and 3mp together and factor the trinomial : )
4m^2 + 7mp + 3p^2
I guess using distributive property backwards :)
4m (m+p)
+
3p (m+p)
=(4m+3p)(m+p)
To factor the expression 4m^2 + 4mp + 3mp + 3p^2 using the distributive property, we can look for common factors among the terms.
First, let's group the terms with a common factor together:
(4m^2 + 4mp) + (3mp + 3p^2)
Now, we factor out the common factors from each group:
4m(m + p) + 3p(m + p)
Notice that both groups have a factor of (m + p). Now, we can factor out (m + p) from the expression:
(m + p)(4m + 3p)
So the fully factored form of 4m^2 + 4mp + 3mp + 3p^2 using the distributive property is (m + p)(4m + 3p).