Write a balance equation between ferous ammonium sulphate and kMNO4
10Fe(NH4)2(SO4)2 + 2KMnO4 + 8H2SO4 ==> 10FeNH4(SO4)2 + 2MnSO4 + 8H2O + K2SO4 + 5(NH4)2SO4
Check that.
To write a balanced equation between ferric ammonium sulfate and KMnO4, we need to determine the stoichiometry of the reaction.
First, let's write the formulas of the compounds involved:
Ferric ammonium sulfate: (NH4)2Fe(SO4)2
Potassium permanganate: KMnO4
Now, let's balance the equation step by step:
1. Start by balancing the elements other than oxygen and hydrogen:
(NH4)2Fe(SO4)2 + KMnO4 → K(Fe(SO4)2) + MnO4
2. Next, balance oxygen by adding water (H2O):
(NH4)2Fe(SO4)2 + KMnO4 → K(Fe(SO4)2) + MnO4 + H2O
3. Now, let's balance hydrogen by adding H+ ions:
(NH4)2Fe(SO4)2 + KMnO4 → K(Fe(SO4)2) + MnO4 + 8H+
4. Finally, balance the charge by adding electrons (e-):
(NH4)2Fe(SO4)2 + KMnO4 + 8H+ → K(Fe(SO4)2) + MnO4 + 8H+ + 8e-
The balanced equation is:
(NH4)2Fe(SO4)2 + KMnO4 + 8H+ → K(Fe(SO4)2) + MnO4 + 8H+ + 8e-
Please note that this equation may not represent an actual reaction, and it is always important to verify the reaction conditions and consider the oxidation states of the elements involved.
The balanced equation between ferrous ammonium sulfate (Fe(NH4)2(SO4)2) and KMnO4 (potassium permanganate) is as follows:
5Fe(NH4)2(SO4)2 + 8KMnO4 + 18H2SO4 → 5Fe2(SO4)3 + 8MnSO4 + K2SO4 + 10NH4HSO4 + 8H2O
Please note that this is a balanced equation, where the coefficients have been adjusted to ensure that the number of atoms on both sides of the equation is equal.