Show that there is at least one point of intersection between the parabola y = −2(x + 1)2 − 5, where
y = f(x), and the straight line y = mx − 7, where y = f(x).
m x -7 = -2(x^2+2x +1) -5
m x -7 = -2x^2 -4x -7
m x = -2x^2 -4x
0 = -2x^2 -(m+4) x
x = 0 is always a solution