A particular Chemistry book costs $6 less than a particular Physics book. Two such Chemistry books
and three such Physics books cost a total of $123. Construct two simultaneous equations and solve
them using the substitution method. Show your working.
I just need help constructing the simultaneous equations. I should be fine with solving them, thank you :)
Just turn the words into math.
A particular Chemistry book costs $6 less than a particular Physics book
c = p-6
Two Chemistry books and three Physics books cost $123
2c+3p = 123
now substitute and crank it out
Thank you :)
Let's assume that the cost of the Physics book is "x" dollars.
According to the problem, the Chemistry book costs $6 less than the Physics book. Therefore, the cost of the Chemistry book would be "x - $6" dollars.
Now, let's calculate the total cost of two Chemistry books: 2 * (x - $6) = 2x - $12
Similarly, the total cost of three Physics books would be 3x.
According to the problem, the total cost of two Chemistry books and three Physics books is $123.
So, we can set up the following equation:
2x - $12 + 3x = $123
Now, you can proceed to solve the equation using the substitution method.
Sure! To construct the simultaneous equations, let's assign variables to represent the unknowns.
Let's assume:
C = The cost of a particular Chemistry book
P = The cost of a particular Physics book
From the given information, we can deduce two equations:
Equation 1: "A particular Chemistry book costs $6 less than a particular Physics book."
C = P - 6
Equation 2: "Two Chemistry books and three Physics books cost a total of $123."
2C + 3P = 123
So, the two simultaneous equations are:
1) C = P - 6
2) 2C + 3P = 123
You can solve these equations using the substitution method or any other method of your choice.