An elastic chord can be stretched to its elastic limit by a load of 8.0N. Assuming it gives an extension 250cm when a load of 0.4N is hung. What would be the chord length when a force of 2.8N is applied?

Length = 250cm/0.4N * 2.8N = cm.

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To find the chord length when a force of 2.8N is applied, we can start by calculating the extension produced by the load of 0.4N. We are given that the load of 0.4N produces an extension of 250cm.

Using this information, we can find the extension per unit force:
Extension per unit force = (Extension produced by load of 0.4N) / (Load of 0.4N)
Extension per unit force = 250cm / 0.4N
Extension per unit force = 625 cm/N

Now, we can use the extension per unit force to find the extension produced by the load of 2.8N:
Extension produced by load of 2.8N = (Extension per unit force) * (Load of 2.8N)
Extension produced by load of 2.8N = 625 cm/N * 2.8N
Extension produced by load of 2.8N = 1750 cm

Finally, we can calculate the chord length when a force of 2.8N is applied:
Chord length = (Initial chord length) + (Extension produced by load of 2.8N)
(Note: Initial chord length is the chord length without any applied force)
Since the problem does not provide the initial chord length, we cannot calculate the final chord length.

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