IF 24.5 mL of the .10M NaOH solutino is required to reach the endpoint in a titration with an unknown monoprotic acid, how many moles of the acid were present?

Question

IF 24.5 mL of the .10M NaOH solutino is required to reach the endpoint in a titration with an unknown monoprotic acid, how many moles of the acid were present?

Answer 1

mols NaOH = M x L = ?

For a monoprotic acid, mols acid = mols base.

Answer 2

Well, well, well, looks like someone is having a titration party! Let's break it down, shall we?

We know the volume of NaOH used is 24.5 mL, and the concentration of NaOH is 0.10 M. So, to find the number of moles of NaOH, we can use the good old formula:

moles = concentration x volume

Plugging in the values, we get:

moles of NaOH = 0.10 M x 24.5 mL

Now, since the acid is monoprotic, the stoichiometry of the reaction should be 1:1. That means, for every mole of NaOH used, there is one mole of acid reacting.

So, the number of moles of the acid present is also 0.10 M x 24.5 mL.

Now, let's do the math and get a serious answer:

Answer 3

To determine the number of moles of the unknown monoprotic acid present, you can use the equation:

Moles of acid = Volume of NaOH (in liters) × Molarity of NaOH

First, convert the volume of NaOH from milliliters to liters:

24.5 mL ÷ 1000 mL/L = 0.0245 L

Next, substitute the values into the equation:

Moles of acid = 0.0245 L × 0.10 mol/L

Moles of acid = 0.00245 mol

Therefore, there were 0.00245 moles of the unknown monoprotic acid present.

Answer 4

To determine the number of moles of the unknown monoprotic acid present, we need to use the concept of stoichiometry, which involves the balanced chemical equation for the reaction between the acid and NaOH. However, since we don't have the balanced equation, we can make use of the information given in the question.

We are given the volume of NaOH solution that reacted, which is 24.5 mL. We also know the concentration of the NaOH solution, which is 0.10 M (moles per liter).

To calculate the number of moles, we first convert the volume from milliliters to liters by dividing by 1000:

24.5 mL ÷ 1000 = 0.0245 L

Next, we can use the equation:

moles = concentration × volume

Substituting the values into the equation:

moles of NaOH = 0.10 M × 0.0245 L

Thus, we find that the number of moles of NaOH is:

moles of NaOH = 0.00245 mol

Since NaOH is a monoprotic base, it reacts in a 1:1 ratio with the unknown monoprotic acid. Therefore, the number of moles of the unknown acid is also 0.00245 mol.

Therefore, there were 0.00245 moles of the unknown monoprotic acid present in the solution.