iam a 3 digit number. my tens digit is five more than my ones digit. my hundreds digit is eight less than my tens. what number am i?
Let's solve this step-by-step:
Let's assume the ones digit is "x".
The tens digit is "x + 5" since it is five more than the ones digit.
The hundreds digit is "x + 5 - 8" since it is eight less than the tens digit.
So the number can be represented as "x + 5 - 8" + (x + 5) + x.
Simplifying the expression, we get:
3x + 2 = 3 digit number.
Since you mentioned that the number is a 3-digit number, we need to find the value of x that makes 3x + 2 a 3-digit number.
The maximum value that x can take is 3, as any value greater than 3 would make 3x + 2 a 4-digit number.
So, the number you are is 3x + 2 = 3(3) + 2 = 9 + 2 = 11.
Therefore, the number you are is 11.
To find the number that satisfies the given conditions, let's break down the information and solve step by step:
1. "My tens digit is five more than my ones digit."
Let's assume the ones digit as 'x'. Therefore, the tens digit would be 'x + 5'.
2. "My hundreds digit is eight less than my tens."
Similarly, the tens digit is 'x + 5'. Therefore, the hundreds digit would be '(x + 5) - 8' or 'x - 3'.
Now, we have all the digits:
Hundreds digit: x - 3
Tens digit: x + 5
Ones digit: x
To form a 3-digit number, the hundreds digit should not be 0. Therefore, let's assume x as 4 (you can try any other digit as well).
Hundreds digit: 4 - 3 = 1
Tens digit: 4 + 5 = 9
Ones digit: 4
So, the number satisfying the given conditions is 194.
tens must be either 9 or 8, making the hundreds 1 or 0.
Think you can fill in the ones digit now?