If an aqueous solution is 5.08 % by weight in sodium chloride and contains 1.79 g of sodium chloride, what mass of water is present in the solution?
.0508*(masswater+1.79)=1.79
solve for mass water.
To find the mass of water present in the solution, we need to subtract the mass of sodium chloride from the total mass of the solution.
First, let's calculate the total mass of the solution:
Total mass of solution = mass of sodium chloride / percentage of sodium chloride
Total mass of solution = 1.79 g / 0.0508 = 35.236 g
Next, we can find the mass of water in the solution:
Mass of water = Total mass of solution - Mass of sodium chloride
Mass of water = 35.236 g - 1.79 g = 33.446 g
Therefore, there is 33.446 grams of water present in the solution.