The temperature of a lead fishing weight rises from 26 C to 38 C as it absorbs 11.3 J of heat. What is the mass of the fishing weight in grams? ( The specific heat capacity of lead is 0.128 J /g C )
7.36
q=mc*delta t. you are given all, solve for mass m.
To find the mass of the fishing weight, we can use the formula for heat, which is given by:
Q = m * C * ΔT
Where:
Q is the amount of heat absorbed (11.3 J)
m is the mass of the fishing weight (in grams)
C is the specific heat capacity of lead (0.128 J /g C)
ΔT is the change in temperature (38 C - 26 C = 12 C)
Rearranging the formula, we have:
m = Q / (C * ΔT)
Substituting in the given values, we can calculate the mass of the fishing weight:
m = 11.3 J / (0.128 J /g C * 12 C)
m = 11.3 g / (1.536 g)
m ≈ 7.36 grams
Therefore, the mass of the fishing weight is approximately 7.36 grams.
To find the mass of the fishing weight, we can use the equation for heat transfer:
Q = m * c * ΔT
where:
Q is the heat absorbed (11.3 J),
m is the mass of the fishing weight (unknown),
c is the specific heat capacity of lead (0.128 J/g°C),
and ΔT is the change in temperature (38°C - 26°C = 12°C).
Rearranging the equation, we can solve for mass:
m = Q / (c * ΔT)
Plugging in the known values:
m = 11.3 J / (0.128 J/g°C * 12°C)
To calculate the mass, divide 11.3 J by the product of 0.128 J/g°C and 12°C:
m = 11.3 J / (0.128 J/g°C * 12°C) ≈ 74 g
Therefore, the mass of the fishing weight is approximately 74 grams.