Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child?

Just tell me the equation.

y = 12 years

Child = y
Father = y + 32
Year of Father = x
Year difference = z

3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -

z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4

In 4 years, the age of the father will be 3 times the age of the child.

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What is the equation tho

can someone tell me what the equation is

HEY (I need the equation!)

hey (what is the equation)

z = ((y + 3(y+32)) / 3) - (y + 32)

uhm

To solve the problem, we need to determine the number of years it will take for the father's age to be three times the child's age.

Let's represent the number of years as "x".

The age of the child is currently 12 years old. So, after "x" years, the child's age will be 12 + x.

The age of the father is currently 12 + 32 = 44 years old. So, after "x" years, the father's age will be 44 + x.

According to the problem, the father's age after "x" years will be three times the child's age after "x" years. Therefore, the equation is:

44 + x = 3(12 + x)

This equation represents the relationship between the child's age and the father's age after "x" years. Now, you can solve this equation to find the value of "x" and determine exactly how many years it will take for the father's age to be three times the child's age.