Maths
posted by Ranya
Mrs jasmine Invested $4000 in a building society which paid simple interest at a rate of 7.25% per annum to its investors. After 2 years, the rate was increased to 7.6% per annum. Find the amount she had T the end of 7 years

John
Do the first 2 years at the regular amount then ADD it to the final five years at the new amount. Both parts using the simple interest equation.

Henry
P1 = Po + Po*r*t = 4000 + 4000*0.0725*2 = $4580 After 2 yrs.
P = Po + Po*r*t = 4580 + 4580*0.076*5 = Amt. after 7 yrs.
After 2 years, the account becomes a new account with an initial investment of $4580 for 5 years. 
Anonymous
6320.4

Anonymous
6100

Hanzalah
Interest before the rate was changed=4000x7.25x2/100
=$580
Interest after the rate was changed=4000x7.6x5/100
=$1520
Total Interest=$1520+$580
=$2100
Total money Mrs. Jasmine has after 7 years=$4000+$1520
=$6100 
Hanzalah
The above question I answered had a typing mistake. The total money Mrs. Jasmine has after 7 years is=$4000+$2100
=$6100
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