Let g(x)=3x+2 and f(x)=(x-2)/3 Find the value. f(g(0))
I think I figured out part of it.
g(0)=3(0)+2=2
g(2)=3(2)+2=8
f(8)=((8)-2)/3=6/3=2
If this is correct, idk where to go from here.
Your first step, g(0)=3(0)+2=2, is correct.
f(g(0)) means that you plug in the value of 'g(0)' as x in f(x).
g(0) = 2
f(g(0)) = f(2) = (2-2)/3 = 0
This is all your question asks for, but these functions are actually inverses of each other. So f(g(x)) and g(f(x)) will always be equal to x.
I actualy found a khan academy thing that helped me out a few minutes ago, before i saw this, but thank you anyways! <3
You have made the correct calculations so far!
To find the value of f(g(0)), we need to substitute the value of g(0) into f(x). We have determined that g(0) is equal to 2.
Now, we substitute 2 into f(x) to get:
f(g(0)) = f(2)
Given that f(x) = (x-2)/3, we can replace x with 2 in the equation:
f(2) = (2-2)/3
Simplifying further, we get:
f(2) = 0/3
And any number divided by 3 is 0, so:
f(2) = 0
Therefore, the value of f(g(0)) is 0.