A camcorder has a power rating of 16 watts. If the output voltage from its battery is 4 volts, what current does it use?
A 1.5m wire carries a 9 A current when a potential difference of 89 V is applied. What is the resistance of the wire?
The current in a hair dryer measures 10 amps. The resistance of the hair dryer is 8 ohms. What is the voltage?
1. P = V*I.
16 = 4*I,
I = ?
3. V = I*R.
2. R = V/I = 89/9.
To determine the current used by the camcorder, we can use Ohm's Law, which states that the current flowing through a conductor is equal to the voltage across it divided by its resistance. In this case, as the camcorder operates on DC (direct current) power, we can assume that its resistance remains constant.
The formula for finding the current is:
I = V / R
Where:
I is the current (in amperes, represented by A),
V is the voltage (in volts, represented by V),
R is the resistance (in ohms, represented by Ω).
The problem provides us with the power rating of the camcorder, not the resistance. However, we can calculate the resistance using the power rating and the given voltage. The power formula is:
P = V * I
Rearranging the formula, we can solve for resistance:
R = V / I
Now, we can substitute the given power rating (P = 16 watts) and voltage (V = 4 volts) into the formula to calculate resistance:
R = 4V / 16W
R = 0.25 Ω
Next, we can rearrange Ohm's Law to solve for current (I) using the known voltage and resistance values:
I = V / R
I = 4V / 0.25 Ω
I = 16 A
Therefore, the camcorder uses a current of 16 amperes (16A) when operating at a power rating of 16 watts and an output voltage of 4 volts.