Question

Can somebody explain to me how 2(u^2)(sin2θ)/g = (u^2)(sinθ)^2/(2g) become 4sin2θ = (sinθ)^2?

Answer 1

2(u^2)(sin2θ)/g = (u^2)(sinθ)^2/(2g)

multiply both sides by 2 g
4 u^2 sin 2θ = u^2 (sinθ)^2
divide both sides by u^2
4 sin 2θ = (sin θ)^2