The amount of k2Cr2O7 required to prepare 100 ml of its 0.05 N solution
To determine the amount of K2Cr2O7 required to prepare a 0.05 N (Normal) solution, we need to know the molar mass of K2Cr2O7 and the volume of the solution we are preparing.
K2Cr2O7 has a molar mass of 294.18 g/mol.
A 0.05 N solution means that there are 0.05 moles of K2Cr2O7 present in 1 liter (1000 ml) of the solution.
We have the volume of the solution as 100 ml (0.1 L).
First, let's calculate the number of moles required for 0.1 L of the solution:
moles = N x volume (in L)
moles = 0.05 mol/L x 0.1 L
moles = 0.005 mol
Now we can calculate the amount of K2Cr2O7 required in grams:
grams = moles x molar mass
grams = 0.005 mol x 294.18 g/mol
grams = 1.4709 g
Therefore, you would need approximately 1.4709 grams of K2Cr2O7 to prepare a 100 ml solution of 0.05 N concentration.