Mrs lee is four times as old as her son. Her son is 36 years old younger than her. How many years ago was mrs lee seven times as old as her son
Son's age = x
Mrs Lee's age = 4x
As per the question,
4x = x + 36
=> 3x = 36
=> x = 12
=> x = 12, 4x = 48
Now, taking the number of years required as y:
(4x - y) = 7(x - y)
=> (48 - y) = 7(12 - y)
=> 48 + 6y = 84
=> 6y = 36
=> y = 6
Hence, the given case was satisfied six years ago.
To find the number of years ago when Mrs. Lee was seven times as old as her son, we will first determine their current ages.
Let's assume the son's current age is x years.
According to the given information, Mrs. Lee is four times as old as her son, so her current age is 4x years.
It is also mentioned that the son is 36 years younger than Mrs. Lee. This means the age difference between them is 36 years.
We can set up an equation to represent this:
Mrs. Lee's age - Son's age = Age difference
4x - x = 36
Simplifying the equation, we have:
3x = 36
Dividing both sides by 3, we find:
x = 12
Therefore, the son's current age is 12 years, and Mrs. Lee's current age is 4 * 12 = 48 years.
Now, to determine the number of years ago when Mrs. Lee was seven times as old as her son, we need to set up a new equation.
Let's assume that t years ago, Mrs. Lee was seven times as old as her son.
At that time, Mrs. Lee's age would have been (48 - t) years, and her son's age would have been (12 - t) years.
According to the given condition, Mrs. Lee was seven times as old as her son, so we can write the equation:
48 - t = 7(12 - t)
Expanding the equation, we get:
48 - t = 84 - 7t
To solve for t, we can simplify the equation by combining like terms:
6t = 84 - 48
6t = 36
Dividing both sides by 6, we have:
t = 36/6
t = 6
Therefore, six years ago, Mrs. Lee was seven times as old as her son.