Determine whether the ordered pair is a solution of the linear inequality.

9)x<2;(-1,0)
13)3y>5x-12;(-6,1)
Can someone help me with these two question please!!?

(-1,0) is a solution to x < 2, because -1 is the x coordinate and it's less than 2.

For this coordinate, the equation evaluates to 3(1) > 5(-6) - 12, which is

3 > -30 - 12,

so (-6,1) is a solution because 3 > -30-12.

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Of course! I can help you with these two questions.

To determine whether an ordered pair is a solution of a linear inequality, we need to substitute the values of the ordered pair into the inequality and see if it is true or false.

Let's start with question 9:
The given inequality is x<2, and the ordered pair is (-1,0).
To check if (-1,0) is a solution, we substitute the values -1 for x and 0 for y in the inequality x<2:
-1 < 2
This statement is true, so (-1,0) is indeed a solution to the inequality x<2.

Now let's move on to question 13:
The given inequality is 3y > 5x - 12, and the ordered pair is (-6,1).
To check if (-6,1) is a solution, we substitute -6 for x and 1 for y in the inequality 3y > 5x - 12:
3(1) > 5(-6) - 12
3 > -30 - 12
3 > -42
This statement is also true, so (-6,1) is a solution to the inequality 3y > 5x - 12.

In summary, the ordered pair (-1,0) is a solution to the inequality x<2, and the ordered pair (-6,1) is a solution to the inequality 3y > 5x - 12.