Express as a single logarithm
2log3 + 4log2
I'm confused as to how to do this, I keep getting the wrong answer. Thank you!
a log(b) = log(b^a)
log(a) + log(b) = log(a*b)
log(3^2) + log(2^4) = log(9 * 16)
Well, let me "log" into this problem and help you out! To express the expression 2log3 + 4log2 as a single logarithm, we can use the logarithm properties.
First, let's rewrite the expression using the product rule of logarithms:
2log3 + 4log2 = log3^2 + log2^4
Then, applying the power rule of logarithms:
= log9 + log16
Finally, we can combine the logarithms using the sum rule:
= log9 * 16
Therefore, the expression 2log3 + 4log2 can be expressed as a single logarithm: log9 * 16.
To express 2log3 + 4log2 as a single logarithm, we can use the properties of logarithms. Specifically, we can use the following two rules:
1. The product rule: loga(b) + loga(c) = loga(b * c)
2. The power rule: n * loga(b) = loga(b^n)
Let's use these rules to simplify the expression:
2log3 + 4log2
Using the power rule, we can rewrite the expression as:
log3(2^2) + log2(4^4)
Simplifying the exponents, we get:
log3(4) + log2(256)
Now, using the product rule, we can combine the logarithms:
log3(4 * 256)
Simplifying the multiplication, we have:
log3(1024)
Therefore, 2log3 + 4log2 simplifies to log3(1024).
To express the expression 2log3 + 4log2 as a single logarithm, you can use the properties of logarithms. The two properties we will use are:
1. The product rule: logₐ(x * y) = logₐ(x) + logₐ(y).
2. The power rule: logₐ(x^y) = y * logₐ(x).
Let's apply these properties to the expression 2log3 + 4log2:
2log3 + 4log2
Using the product rule on both terms:
= log₃(3^2) + log₂(2^4)
Simplifying further:
= log₃(9) + log₂(16)
Now, to combine the two logarithms into a single logarithm, we can use the product rule again:
= log₃(9 * 2^4)
Simplifying:
= log₃(9 * 16)
Final Answer:
= log₃(144)
Therefore, 2log3 + 4log2 can be expressed as a single logarithm: log₃(144).
Remember to always apply logarithmic properties and simplify as much as possible to get the correct answer.