Three vectors are shown in the figure below, but they are not drawn to scale. The sum of the three vectors is R = F1 + F2 + F3. If Ry = 0 and F2 = 0.2F3, find Rx in terms of F1. the Answer Keyis 0.327.can somebody show me how to get to the answer key. I try my best to describe the figure. the figure looks like an x with an exra line draw from the center of the x downward in other word like an upside down star. F1 is that line and on the left of that line is 30degree. F2 point on the north-west side and F3 point on the north-east side. Please help.I'm stuck.

Opps, I solve it for Rx in terms of F3, you want it in terms of F1

Rx=F1*sin30-F2
= .5F1-.2F2
but F2=.2F3=.2(-F1*cos30)
Rx=.5F1-.2* cos30 F1
=F1(.5-.2*.866)=.327F1

I need the figure.

do you know anyway for me to show you the figure on this site bobpursley?I had try copy and pasted but not show up and I can't paste any link on this site either.

bobpursley I just send you an email. check and see did you receive it yet

so Ry is zero, which means cos30*F1=-F3

and F2 = 0.2F3, so
Rx=???F3 is the question
Rx=sin30*F1 from the figure.
Rx=.5F1-F2=.3(-F3/cos30)-.2F3 and you have it.
check my thinking.

I don't get it what is the value forF1? can you show step by step with number?

To find Rx in terms of F1, we need to analyze the given information and use vector addition.

1. Begin by drawing a diagram illustrating the vectors F1, F2, and F3 as described.

2. Since Ry = 0, this means that the vertical components of the vectors cancel each other out. Thus, we can write the equation: F1sin(30°) + F2sin(θ) + F3sin(θ) = 0, where θ is the angle that F2 and F3 make with the horizontal axis.

3. We know that F2 = 0.2F3. Substituting this into the equation from step 2, we get: F1sin(30°) + (0.2F3)sin(θ) + F3sin(θ) = 0.

4. Combining the terms with sin(θ), we have: F1sin(30°) + (0.2F3 + F3)sin(θ) = 0.

5. Simplifying further, we get: F1sin(30°) + (1.2F3)sin(θ) = 0.

6. To find Rx, we need to calculate the horizontal component of the vectors. Rx = F1cos(30°) + F2cos(θ) + F3cos(θ).

7. Since F2 is 0.2F3, we can rewrite Rx as: Rx = F1cos(30°) + (0.2F3)cos(θ) + F3cos(θ).

8. Now, we need to eliminate θ from the equations. We can do this by dividing the equation from step 6 by the equation from step 5. This gives us: Rx / (F1cos(30°) + (0.2F3)cos(θ) + F3cos(θ)) = (F1sin(30°) + (1.2F3)sin(θ)) / 0.

9. Since Ry = 0 (as given), the right side of the equation becomes 0. Therefore, we have: Rx / (F1cos(30°) + (0.2F3)cos(θ) + F3cos(θ)) = 0.

10. Rearranging the equation, we get: Rx = 0.

Therefore, the answer Rx, in terms of F1, is 0.