A rectangular table is twice as long as it is wide. What is the perimeter of a table if it measures 1.5ft by 3ft ?
P = 2L + 2W
P = 2(1.5) + 2(3)
P = ________ ft.
To find the perimeter of a rectangular table, we add up the lengths of all four sides.
Given that the table measures 1.5ft by 3ft, we can determine the length and width of the table.
Let's denote the width of the table as w.
According to the problem, the length of the table is twice the width.
So, the length of the table would be 2w.
Given that the table measures 1.5ft by 3ft, we have:
w = 1.5ft (width)
2w = 3ft (length)
To find the perimeter, we sum up all sides:
Perimeter = 2(length + width)
Substituting the values, we have:
Perimeter = 2(1.5ft + 3ft)
Perimeter = 2(4.5ft)
Perimeter = 9ft
Therefore, the perimeter of the table is 9 feet.
To find the perimeter of the table, you need to add up the length of all the sides. Let's call the width of the table "w" and the length "l."
Given that the table is twice as long as it is wide, we can express this as l = 2w.
Now, we know that the table measures 1.5ft by 3ft. We can substitute these values into our equation to find the length:
1.5 = 2w
To solve for w, we divide both sides of the equation by 2:
w = 1.5 / 2
w = 0.75
Therefore, the width of the table is 0.75ft.
Now, we can substitute the width into our equation for the length:
l = 2 * 0.75
l = 1.5
The length of the table is 1.5ft.
To find the perimeter, we add up the length of all four sides:
Perimeter = 2l + 2w
Perimeter = 2(1.5) + 2(0.75)
Perimeter = 3 + 1.5 + 1.5
Perimeter = 6
Therefore, the perimeter of the table is 6 feet.