Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Chemistry
Radon-222 has a half-life of 3.8days. What gram of radio isotopes will remain after 11.4days if you started out with 16 grams of the sample?
1 answer
left=16e
-.693*11.4/3.8
left= 16(.125)= ....
You can
ask a new question
or
answer this question
.
Similar Questions
The half life of radon 222 is 3.82 days. If the initial mass of a sample of radon 222 is 198.72 grams, how much will remain
Top answer:
Yes
Read more.
Radon-222 is a radioactive gas with a half-life of 4 days. Approximately how much of a 40 g sample of radon-222 would remain
Top answer:
To determine the amount of radon-222 remaining after 12 days, we need to consider its half-life. The
Read more.
The half-life of radon-222 is 3.82 days. If a sample of gas contains 4.38ug of radon-222, how much will remain in the sample
Top answer:
k = 0.693/t<sub>1/2</sub> Substitute k into the following: ln(No/N) = kt No = 4.38 ug. N = solve for
Read more.
If radon-222 has a half-life of 3.8 days, determine how long it takes for only 1/8 of a sample to remain.
Top answer:
Find k from the following. k = 0.693/t<sub>1/2</sub> Then substitute into the following ln(No/N) =
Read more.
The radioisotope radon-222 has a half-life of 3.8 days. How much of a 98.4 g sample of radon -222 would be left after
Top answer:
98.4 * (1/2)^(19/3.8) = 3.075 g
Read more.
The radioisotope radon-222 has a half-life of 3.8 days. How much of a 65-g sample of radon-222 would be left after approximately
Top answer:
amount left=65*e^(-.693*15/3.8) put this in your google search window: 65*e^(-.693*15/3.8)=
Read more.
The half-life of radon-222 is 3.8 days. How much of a 300 gram sample is left after 14.8 days?
Top answer:
see https://www.jiskha.com/questions/1751649/300-1-2-14-8-3-8-20-17-g
Read more.
The half-life of radon-222 is 3.8 days. How much of a 300 gram sample is left after 14.8
days?
Top answer:
300*(1/2)^(14.8/3.8) = 20.17 g
Read more.
The half-life of radon-222 is about four days. After how many days is the amount of radon-222 equal to one-sixteenth of its
Top answer:
0 days = 1 gram. Start with 1 gram. 4 dais = 1/2 g 8 days = 1/4 g 12 days = 1/8 g 16days = 1/16 g
Read more.
Radon-222 is an isotope that undergoes radioactive decay. For a sample initially containing 450milligrams of radon-222, the
Top answer:
According to the model m(t)=450(0.83)t, the mass of radon-222 in the sample decreases over time.
Read more.
Related Questions
a)indium-115 has a half life of 4.5 hours. if you start with a 12.0-mg sample of indium-115, how much will remain after 13.5
sodium-24 has a half-life of 15 hours how much of a 20 gram sample would remain after 30 hours? and how do you solve this?
Sam is comparing the half-life of two isotopes of uranium. The half-life of Uranium-238 is 4.5 × 10° years The half-life of
Radon-222 undergoes alpha decay.what is the nuclear equation
the half-life of radon-222 is 3.823 days. what was the original mass if 0.050g remains after 7.646 days?
sam is comparing the half-life of two isotopes of uranium. The half-life of uranium-238 is 4.5 × 10⁹ years. The half- life of
Sam is comparing the half-life of two isotopes of uranium. The half-life of Uranium-238 is 4.5×109 years. The half-life of
Alice reads an equal number of pages of a storybook each day. After 8days, she has 5/6 of the storybook left to read. Another
Sam is comparing the half-life of two isotopes of uranium. The half-life of Uranium-238 is 4.5×10^9 years. The half-life of
Sam is comparing the half-life of two isotopes of uranium. The half-life of Uranium-238 is 4.5 x 10^9 years. The half-life of