a model of a rocket is 1.77 m high.This height is 1.6% of the actual height of the rocket. what is the usual height of the rocket?
1.6% = 0.016
so,
0.016h = 1.77
h = 110.6 meters
This represents the actual height. No idea what the "usual" height is ...
To find the usual (or actual) height of the rocket, we need to solve for it using the given information. Let's assume the usual height of the rocket is represented by "x" meters.
According to the given information, the height of the model rocket is 1.77 meters, which is equal to 1.6% of the usual height.
We can set up the following equation to solve for the usual height:
1.77 = 0.016x
To solve for x, first, we need to isolate it.
Divide both sides of the equation by 0.016:
(1.77 / 0.016) = 0.016x / 0.016
110.625 = x
Therefore, the usual height of the rocket is approximately 110.625 meters.
To find the usual height of the rocket, we need to use the given information that the model height is 1.6% of the actual height.
Let's set up an equation to solve for the usual height of the rocket.
Let x be the usual height of the rocket.
We can write the equation as:
1.6% of x = 1.77 m
To solve for x, we need to convert the percentage to a decimal. We can do this by dividing 1.6 by 100, which gives us 0.016.
0.016x = 1.77
Now, we can solve for x by dividing both sides of the equation by 0.016:
x = 1.77 / 0.016
Calculating this gives us:
x ≈ 110.625
Therefore, the usual height of the rocket is approximately 110.625 meters.