Light photons with energy 7.3 eV strike a metal surface and eject electrons with energy 2.7 eV. What is the Work Function of the metal?
work function= (7.3eV-2.7ev) in ev
divide by 1.6×10−19 to get work function in volts.
The work function of a metal is the minimum energy required to remove an electron from its surface. In this case, the energy of the incident photons is 7.3 eV, while the energy of the ejected electrons is 2.7 eV.
To find the work function of the metal, we need to determine the difference between these two energies.
Work Function = Energy of Incident Photons - Energy of Ejected Electrons
= 7.3 eV - 2.7 eV
= 4.6 eV
Therefore, the work function of the metal is 4.6 eV.
To find the work function of the metal, we can use the equation:
Energy of incident photons = Work function + Energy of ejected electrons
In this case, the energy of the incident photons is given as 7.3 eV and the energy of ejected electrons is given as 2.7 eV. Let's substitute these values into the equation:
7.3 eV = Work function + 2.7 eV
To isolate the work function, we need to move the known value (2.7 eV) to the other side of the equation:
7.3 eV - 2.7 eV = Work function
Now, let's subtract the known value:
4.6 eV = Work function
Therefore, the work function of the metal is 4.6 eV.