Re arrange this to isolate A
H=K+log(A/C)
Thank you
H - K = log(A/C)
H - k = logA - logC
logA = H - K + logC
A = 10^(H - K + logC)
subtracting K ... H - K = log(A/C)
10^(H-K) = A/C ... C [10^(H-K)] = A
To isolate A in the equation H=K+log(A/C), follow these steps:
1. Start with the equation H=K+log(A/C).
2. Subtract K from both sides to get rid of it on the right side: H - K = log(A/C).
3. Rewrite the equation to exponential form, which will help isolate A: 10^(H - K) = 10^(log(A/C)).
4. According to the logarithmic property, 10^(log(A/C)) simplifies to A/C: 10^(H - K) = A/C.
5. Now, multiply both sides of the equation by C: C * 10^(H - K) = A.
This will isolate A on one side of the equation.
6. Finally, the equation is rearranged to isolate A:
A = C * 10^(H - K).
To isolate A in the equation H=K+log(A/C), you can follow these steps:
Step 1: Start by subtracting K from both sides of the equation
H - K = log(A/C)
Step 2: Exponentiate both sides of the equation using base 10. This will eliminate the logarithm.
10^(H - K) = A/C
Step 3: Multiply both sides of the equation by C to isolate A.
C * 10^(H - K) = A