Three numbers multiplied together equal 2880.
A X B X C= 2880 A X B=360 A X C= 160
A=
B=
C=
Hint :
if ABC = 2880 and AB = 360
how about finding ABC/(AB) = 2880/360
C = ....
Now do the same with AC = 160 , so now you also have B
From there it is easy to find A
A= 20
B= 18
C= 8
You got it
To find the values of A, B, and C, we can use the information provided.
We know that A * B * C = 2880, A * B = 360, and A * C = 160.
Let's solve for A first. We can divide both sides of the equation A * B = 360 by B to isolate A:
(A * B) / B = 360 / B
A = 360 / B
Now we can substitute this value of A in the equation A * C = 160:
(360 / B) * C = 160
We can simplify this equation by multiplying both sides by B:
(360 * C) / B = 160
Next, let's solve for B. We can isolate B by multiplying both sides of the equation by B:
B * ((360 * C) / B) = B * 160
360 * C = 160B
Now divide both sides of the equation by 160 to get B alone:
(360 * C) / 160 = B
Finally, let's solve for C. We know that A * C = 160, so we can isolate C by dividing both sides of the equation by A:
(A * C) / A = 160 / A
C = 160 / A
Now we can substitute the value of A we found earlier, A = 360 / B, into the equation for C:
C = 160 / (360 / B)
C = (160 * B) / 360
To summarize:
A = 360 / B
B = (360 * C) / 160
C = (160 * B) / 360
Now we can start plugging in different values for B and solving for A and C. Since A, B, and C are integers and their product is 2880, we can look for factors of 2880.
A few possible combinations of A, B, and C are:
A= 36, B = 10, C = 8
A= 24, B = 15, C = 8
A= 20, B= 18, C= 8
You can try plugging in these values into the original equations to verify that they satisfy all the conditions.