I have matrix A = -1 0
0 -1
B = 0
1
c = 1
0
find n that A^n * matrix B = C
find A^2014
If you take (-1) out of matrix A as a scalar, you'll notice that A is actually (-1)*I, where I is the identity matrix.
Hence, A^n will be the identity matrix if 'n' is even, and it will be A if 'n' is odd.
A^2014 = I
It's not clear what matrices B and C are in your question, but I think you'll be able to solve it with this information.