A brick is thrown upward from the top of a building at an angle of 19.3◦ above the horizontal and with an initial speed of 22.5 m/s. The acceleration of gravity is 9.8 m/s2 . If the brick is in flight for 3.5 s, how tall is the building? Answer in units of m

just do the vertical problem

Vi = 22.5 sin 19.3 = 7.44 m/s upwards

v = Vi - 9.8 tup
at top v = 0 so
tup = 7.44/9.8 = .759 seconds upward
so how long did it fall from the zero vertical velocity high spot?
t = 3.50 - .759 = 2.74 seconds falling
so how high was it at peak?
fall dist = 4.9 t^2 = 4.9(2.74)^2
= 36.8 meters from peak of trajectory
now subtract the roof to peak of flight
36.8 = roof + (7.44/2)(.759)
36.8 = roof + 2.82
roof = 34 meters

Vo = 22.5m/s[19.3o].

Yo = 22.5*sin19.3 = 7.44 m/s = Ver. component of initial velocity.

Y = Yo + g*Tr = 0 at max. ht. =
7.44 + (-9.8)Tr = 0,
Tr = 0.759 s. = Rise time.

T = 2*Tr = 2 * 0.759 = 1.52s = Time to return to top of roof.

T+Tf = 3.5s.
1.52 + T

Vo = 22.5m/s[19.3o].

Yo = 22.5*sin19.3 = 7.44 m/s = Ver. component of initial velocity.

Y = Yo + g*Tr = 0 at max. ht. =
7.44 + (-9.8)Tr = 0,
Tr = 0.759 s. = Rise time.

T = 2*Tr = 2 * 0.759 = 1.52s = Time to return to top of roof.

T + Tf = 3.5s.
1.52 + Tf = 3.5,
Tf = 1.98s = Fall time from roof to gnd.

h = Yo*Tf + 0.5g*Tf^2.
h = 7.44*1.98 + 4.9*1.98^2 = 34 m. = Ht. of bldg.

My first post was done in error. Please disregard it.

To find the height of the building, we can use the vertical motion equation:

h = v₀y * t + (1/2) * g * t²

where:
h = height of the building
v₀y = initial vertical component of velocity
t = time
g = acceleration due to gravity

First, we need to find the initial vertical component of velocity, v₀y. We can use the given information that the brick is thrown at an angle of 19.3◦ above the horizontal and with an initial speed of 22.5 m/s.

v₀y = v₀ * sin(θ)

where:
v₀ = initial speed
θ = angle of projection

Now we can calculate v₀y:

v₀y = 22.5 m/s * sin(19.3◦)

Next, we need to calculate the height, h, using the given time of 3.5 seconds:

h = (22.5 m/s * sin(19.3◦)) * 3.5 s + (1/2) * (9.8 m/s²) * (3.5 s)²

Simplifying the equation:

h = (22.5 m/s * sin(19.3◦) * 3.5 s) + (1/2) * (9.8 m/s²) * (3.5 s)²

h = (22.5 * sin(19.3) * 3.5) + (0.5 * 9.8 * (3.5)^2)

Calculate the value of sin(19.3) using a scientific calculator or online tool:

h = (22.5 * 0.3316 * 3.5) + (0.5 * 9.8 * (3.5)^2)

Solving the equation:

h = 26.258 * 3.5 + 0.5 * 9.8 * 12.25

h = 91.803 + 60.275

h = 152.078

Therefore, the height of the building is approximately 152.078 meters.