Algebra
posted by Jay
Assume that S/A = 5.2, D/A = .40, N/E = .75 and A = D + E. Solve for N/S.

bobpursley
A=D+E
S/5.2=.4A + N/.75
S/5.2=.4*S/5.2 + N/.75
S(1/5.2.4/5.2)=N/.75
N/S= .75(1/5.2.4/5.2) 
Steve
D = 0.40A
A = D+E = 0.40A+E so E = 0.60A
N = 0.75E = 0.45A
S = 5.2A
N/S = 0.45/5.2 = 45/520
Respond to this Question
Similar Questions

economics
assume that the demand and supplu equations for bushels of wheat are as follows Qd=15(3*P) Qs=1+(4*P) Also assume that, the equilibrium, Qd=Qs solve for equilibrium price by setting quanity demand equal to quanity supplied. what is … 
bobpursly,.math
Ok, assume it equals zero. 2x + 3y 6=0 subtract 3y from each side. add six to each side. divide both sides by two. its how its in the book i'm suppost to solve for x. but how? 
algebra
x+1 x+2 = x+3 ____ _____ ____ 2 3 4 How do I solve this equations? 
math
the sum of a number and 3 times that number is 76. what is that number? 
Algebra II (check)
Assume that no denominator equals 0. (8y^3+27)/(2xy10y+3x15) I don't know how to solve this one. 
Algebra
The last problem I have that I can't solve either and it's driving me nuts. Assume b,c ‚ 0 (4b^2c^3)^4 
algebra
solve the formula for the given letter. Assume all variables represent nonnegative numbers. E=jc^2 solve for c 
Math
We have an important chemsitry test due and I want to make sure that I do not mess up on my algebra. I am dealing with the integrated rate law, but my question is purely algebraically in nature. I hope, somebody can help me. 1) ln(A) … 
Algebra
Assume that S/A=7.0, D/A=.40, N/E=.80 and A = D + E. Solve for N/S. 
algebra
Assume that S/A = 7.0, D/A = .40, N/E = .80 and A = D + E. Solve for N/S.