Physics
posted by Anonymous
A billiard cue ball having velocity of 5.0 cm/s and a mass 0.17 kg approaches a stationary red billiard ball of
mass 0.16 kg. If the cue ball is stationary after their collision, what is the new velocity for the red ball?

Damon
Hey, Google "conservation of momentum"
0.05 m/s * 0.17 kg = v * 0.16 
Henry
Given:
M1 = 0.17kg, V1 = 0.05 m/s.
M2 = 0.16kg, V2 = 0.
V3 = 0. = Velocity of M1 after the collision.
V4 = ? = Velocity of M2(red ball) after the collision.
Momentum before = Momentum after.
M1*V1 + M2*V2 = M1*V3 + M2*V4.
0.17*0.05 + 0.16*0 = 0.17*0 + 0.16*V4,
0.16*V4 = 0.0085,
V4 = ?
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