Physics

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A squirrel sees a BIG acorn being thrown from a tree by a chipmunk and attempts to snatch it. The acorn is thrown from a 10.0 m high branch and with a horizontal velocity of 1.1 m/s. The squirrel on the ground is 5.0 m from the base of the tree. What is the of the squirrel’s average velocity if it grabs the acorn in its mouth just as it touches the ground?

Can someone explain this?

1. bobpursley

So he throws it horizontal.
time in air: 10=1/2 a t^2
t=sqrt(20/9.8) seconds
how far will the acorn travel: 1.1*sqrt(20/9.8)

how far does the squirrel run?
1.1*sqrt(20/9.8) -5
average velocity squirrel ?
distance above/timeto fall

2. |-/

Travel = 1.571429
Distance the squirrel ran = −3.428571
Is this right?

3. bobpursley

I would take numbers to more than two sig digits. Now if the squirrel is on the other side of the tree, distance will be 5+1.6 m. The problem is not clear where the squirrel is.

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