maths
posted by RAJESH
300 gm of water at 25°c is added to 100 gm of ice at 0°c.the temperature of the mixture is?

Arora
Since the subject is 'maths', I'm assuming the energy required for the icetowater conversion is not to be considered
Basically, you have to multiply the fraction of the total masses of the substance with their temperature:
Final Temp. = (300/400)*25 + (100/400)*0
= (3/4)*25
= 18.75 degrees Celsius
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