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300 gm of water at 25°c is added to 100 gm of ice at 0°c.the temperature of the mixture is?

  • maths -

    Since the subject is 'maths', I'm assuming the energy required for the ice-to-water conversion is not to be considered

    Basically, you have to multiply the fraction of the total masses of the substance with their temperature:

    Final Temp. = (300/400)*25 + (100/400)*0
    = (3/4)*25
    = 18.75 degrees Celsius

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