The sum of three times and one is not greater than the sum of twice that number and seven.Find the poosible range of value for the number

3n + 1 </= 2n+ 7

n </= 6

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To find the possible range of values for the number, let's break down the problem and solve it step by step.

Let's assume that the number we're trying to find is "x."

The first part of the problem states that "The sum of three times the number and one is not greater than the sum of twice that number and seven." We can translate this into an equation as follows:
3x + 1 ≤ 2x + 7

To find the possible range of values for x, we need to solve this inequality.

1. Start by subtracting 2x from both sides of the inequality to isolate the x term:
3x - 2x + 1 ≤ 2x - 2x + 7
x + 1 ≤ 7

2. Next, subtract 1 from both sides of the inequality to isolate the x term further:
x + 1 - 1 ≤ 7 - 1
x ≤ 6

Therefore, the possible range of values for the number, x, is any value less than or equal to 6. In interval notation, we can express this as (-∞, 6]. This means that x can be any real number less than or equal to 6, including 6 itself.