Suppose you start an antique car by exerting a force of 300 N on its crank for 0.250s. What angular momentum is given to the engine if the handle of the crank is 0.300 m from the pivot and the force is exerted to create maximum torque the entire time?
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We can use the equation τ = Change in angular momentum/Change in time
To find τ, the torque:
=> Force x Distance
=> 300N * 0.3m = 90Nm
Angular Momentum given = τ*t
= 90*0.250
= 22.5Nms
To find the angular momentum given to the engine, we need to calculate the torque applied by the force and then multiply it by the time of application.
First, let's find the torque. Torque is given by the formula:
Torque = Force x Distance perpendicular to the force
In this case, the handle of the crank is the distance from the pivot point where the force is applied. So, the torque is:
Torque = Force x Distance
Torque = 300 N x 0.300 m
Now, let's calculate the torque:
Torque = 90 N·m
The torque remains constant since it is mentioned that the force is exerted to create maximum torque throughout the entire time.
The angular momentum is given by the formula:
Angular Momentum = Torque x Time
Angular Momentum = 90 N·m x 0.250 s
Now, let's calculate the angular momentum:
Angular Momentum = 22.5 N·m·s
Therefore, the angular momentum given to the engine is 22.5 N·m·s.