the first and last terms of an AP are 6.1 and 7.1 respectively if there are 14 terms in the sequence find its common difference
term(1) = a = 6.1
term(14) = a + 13d = 7.1
6.1 + 13d = 7.1
13d = 1
d = 1/13
term(14) = a + 13d = 7.1
6.1 + 13d = 7.1
13d = 1
d = 1/13