(k + 1/k) ^2 =36
what is k^2 + (1/k)^2
34?
(k+ 1/k)^2
= k^2 + 2(K)(1/k) + (1/k) = 36
k^2 + (1/k)^2 + 2 = 36
so k^2 + (1/k)^2 = 34
you are correct
Thanks
To find the value of k^2 + (1/k)^2, you can start by expanding the expression (k + 1/k)^2 using the formula for squaring a binomial:
(k + 1/k)^2 = k^2 + 2(k)(1/k) + (1/k)^2
Simplifying further:
= k^2 + 2 + (1/k)^2
Now we can see that the expression k^2 + (1/k)^2 is equal to (k + 1/k)^2 - 2:
k^2 + (1/k)^2 = (k + 1/k)^2 - 2
Given that (k + 1/k)^2 = 36 (as stated in the initial equation), we can substitute this value into the expression:
k^2 + (1/k)^2 = 36 - 2
Simplifying:
k^2 + (1/k)^2 = 34
So the value of k^2 + (1/k)^2 is indeed 34.