a ladder 5m long rests against a wall at a height of 4.8m from the ground. Calculate the distance of the foot of thw ladder from the wall
you will draw a wall and then place the ladder by a a little slop on the wall of a higt 4,8 and then by phythagaros theorem you can get the distance
Yes
x^2 + 4.8^2 = 25
To solve this problem, we can use the Pythagorean Theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the ladder forms the hypotenuse, and the wall and the ground form the two other sides of the right triangle.
Let's call the distance from the foot of the ladder to the wall "x". According to the Pythagorean Theorem, we have:
x^2 + 4.8^2 = 5^2
Simplifying the equation, we get:
x^2 + 23.04 = 25
Subtracting 23.04 from both sides, we have:
x^2 = 1.96
Taking the square root of both sides, we find:
x = √1.96
Simplifying the square root, we get:
x ≈ 1.4
Therefore, the distance of the foot of the ladder from the wall is approximately 1.4 meters.