An aluminum block absorbs 1.0 x 104 J of energy from the Sun when its temperature increases by 5.0 °C. What is the mass of the block?
the specific heat capacity of aluminum is 920
Q=1x10^4
c = 9.2 x10^2
△T=5°C
Quantity of heat formula:
Q=mc△T
Rearrange the formula to solve for mass:
m=Q/c△T
m=1x10^4/(9.2x10^2)(5)
m=2.2kg
To determine the mass of the aluminum block, we can use the equation:
Q = m * c * ΔT
Where:
Q = Energy absorbed by the block = 1.0 x 10^4 J
m = mass of the block (unknown)
c = specific heat capacity of aluminum = 920 J/kg°C
ΔT = change in temperature = 5.0 °C
Rearranging the equation to solve for the mass (m), we have:
m = Q / (c * ΔT)
Plugging in the given values:
m = (1.0 x 10^4 J) / (920 J/kg°C * 5.0 °C)
m ≈ 2.17 kg
Therefore, the mass of the aluminum block is approximately 2.17 kg.
To calculate the mass of the aluminum block, we can use the formula:
Q = mcΔT
Where:
Q is the energy absorbed by the block (1.0 x 10^4 J)
m is the mass of the block (unknown)
c is the specific heat capacity of aluminum (920 J/kg·°C)
ΔT is the temperature change (5.0 °C)
Rearranging the formula to solve for mass:
m = Q / (cΔT)
Let's substitute the given values into the formula:
m = (1.0 x 10^4 J) / (920 J/kg·°C * 5.0 °C)
m = 1.0 x 10^4 J / 4600 J/kg
m ≈ 2.17 kg
Therefore, the mass of the aluminum block is approximately 2.17 kg.
10^4 = 920 * m * 5
m = 10,000 /4,600 kg