A compound is formed when 12.2 g Mg combines completely with 5.16 g N. What is the percent composition of this compound? Please show all work and include the percentage of both magnesium and nitrogen.
Don't panic just because this is a science question. If I asked the question this way I'll bet you could answer it. You have 1 lb of apples in a bucket and 1 lb of organges in the bucket; what's the percent apples. You would immediately say 50%. How did you get that.
(mass apples/total mass)*100 = (1 lb/2 lb)*100 = 50%. Do the same thing for this chemistry problem. They want %Mg and %N.Please post your work if you gfet stuck.
it it was complete
percentMg=12.2/(12.2+5.16) * 100
percentN=5.16/(12.2+5.16) * 100
Okay I got
70.28% and 29.7%
Now its telling me to Calculate the percent by mass of carbon in CO2 (carbon dioxide) how do I go about doing that?
what is the mole mass of CO2?
percentC=atomicmassC/molmassCO2 * 100
The mole mass of CO2 is 44.01 g/mol
What do I put as percentC and atomic mass?
To find the percent composition of a compound, we need to determine the mass of each element present in the compound and then calculate the percentage of each element.
Given:
Mass of Mg = 12.2 g
Mass of N = 5.16 g
To calculate the percent composition of magnesium (Mg):
Step 1: Determine the molar mass of magnesium (Mg). The molar mass of Mg is 24.31 g/mol.
Step 2: Calculate the moles of magnesium using the given mass of Mg and its molar mass:
Moles of Mg = Mass of Mg / Molar mass of Mg
= 12.2 g / 24.31 g/mol
= 0.5023 mol
Step 3: To find the percentage of magnesium in the compound, divide the moles of magnesium by the total moles of the compound (1 mol because the compound is formed from a 1:1 ratio of Mg and N):
Percentage of Mg = (moles of Mg / total moles) * 100
= (0.5023 mol / 1 mol) * 100
= 50.23%
Therefore, the percent composition of magnesium in the compound is 50.23%.
Now let's calculate the percent composition of nitrogen (N):
Step 1: Determine the molar mass of nitrogen (N). The molar mass of N is 14.01 g/mol.
Step 2: Calculate the moles of nitrogen using the given mass of N and its molar mass:
Moles of N = Mass of N / Molar mass of N
= 5.16 g / 14.01 g/mol
= 0.3687 mol
Step 3: To find the percentage of nitrogen in the compound, divide the moles of nitrogen by the total moles of the compound (1 mol because the compound is formed from a 1:1 ratio of Mg and N):
Percentage of N = (moles of N / total moles) * 100
= (0.3687 mol / 1 mol) * 100
= 36.87%
Therefore, the percent composition of nitrogen in the compound is 36.87%.
In summary, the compound has a percent composition of 50.23% magnesium and 36.87% nitrogen.