Hi there, can someone please help me with this chemistry problem?
Write the equation for the acid-base reaction that takes place when nitric acid (HNO3) dissolves in H2O. (Include the phase of each substance.)
I got HNO3(aq) + H2O --> H3O+(aq) + NO3−(aq)
but the answer is incorrect
correct.
Sure, let's go through this step by step to find the correct equation for the acid-base reaction when nitric acid (HNO3) dissolves in water (H2O).
When an acid dissolves in water, it typically donates a hydrogen ion (H+) to water, forming a hydronium ion (H3O+). In the case of nitric acid (HNO3), it donates one hydrogen ion. Nitrate ion (NO3-) is the conjugate base formed as a result.
To write the equation, we first need to identify the reactants and products:
Reactant:
Nitric acid (HNO3)
Product:
Hydronium ion (H3O+)
Nitrate ion (NO3-)
Based on this, the balanced equation for the acid-base reaction can be written as:
HNO3(aq) + H2O(l) → H3O+(aq) + NO3-(aq)
Make sure to indicate the phase of each substance. In this case, HNO3 is in the aqueous state (aq) because it is dissolved in water. H2O is in the liquid state (l), H3O+ is in the aqueous state (aq), and NO3- is also in the aqueous state (aq).
So, the correct equation for the acid-base reaction is:
HNO3(aq) + H2O(l) → H3O+(aq) + NO3-(aq)
I hope that helps! Let me know if you have any more questions.