Find the length of the shortest side of triangle ABC drawn given that the perimeter is 22. A=3x+1 B=2x+1 C=x+4
The sum of the given sides must be equal to 22, the perimeter.
Therefore,
(3x + 1) + (2x + 1) + (x + 4) = 22
=> 6x + 6 = 22
Solve for x, and you can find the values of the three sides.