The current carriers in a piece of semiconducting material have a charge of 1.6 x 10^-19C. Calculate the number of charge carriers entering the material per second when the current is 3 microamps so 3 x 10^-6 amps. ?

Please help and do it step by step all parts of questions and use:
T = time(s)
I=current (amps)
Q=net charge on object (Coulombs)
N=no electrons (and write if added or removed from object and how)
E=elementary charge

To calculate the number of charge carriers entering the material per second, we can use the formula:

Q = I * T,

where Q represents the net charge on the object, I represents the current in amps, and T represents the time in seconds.

In this case, we want to find the number of charge carriers entering the material per second, so we need to rearrange the formula to solve for T:

T = Q / I.

First, let's calculate the net charge on the object using the given current of 3 microamps.

I = 3 x 10^-6 amps.

Now, we can substitute the values into the formula:

Q = (3 x 10^-6)Coulombs.

Since each carrier has a charge of 1.6 x 10^-19C, we can calculate the number of carriers by dividing the net charge (Q) by the elementary charge (E):

N = Q / E.

Substituting the values:

N = (3 x 10^-6) / (1.6 x 10^-19).

To simplify the calculation, we can rewrite the equation in scientific notation:

N = (3 / 1.6) x (10^-6 / 10^-19).

N = (3 / 1.6) x (10^(19 - 6)).

N = 1.875 x 10^13.

Therefore, the number of charge carriers entering the material per second when the current is 3 microamps is approximately 1.875 x 10^13 carriers.