chemsitry

posted by hamed

Calculate the work in kilojoules done during a reaction in which the volume expands from 10.0 L to 95.9 L against an external pressure of 2.5 atm.

  1. bobpursley

    what is Pressure*volume?
    85.9*2.5*101kPa*dm^3== 21689750e-6 Pa*L^3

    but what is a Pa? force/m^2=N/m^2
    so Pa*m^3=Joules
    PV=21.7Joules

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