Physics
posted by Will .
What force is required to stop a 1500kg car in a distance of 0.20 m if it is initially moving at 2.2 m/s?

Friction...

work done by force = F d = 0.20 d Joules
kinetic energy = (1/2) m v^2
work done to stop = kinetic energy
0.20 d = (1/2)(1500)(2.2)^2 
V^2 = Vo^2 + 2a*d.
0 = (2.2)^2 + 0.4a,
a = 12.1 m/s^2.
F = M*a = 1500*(12.1) = 18,150 Joules.
The negative sign means the force opposes the motion.
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