Before 5 years a man was 3 years times his boy but after 10 years the father's age will be 6 more than 2 times his boy.
Find the age of the father.
And the age of the son.
(m-5) = 3(b-5)
(m+10) = 6+2(b+10)
Now just solve for their ages.
To find the age of the father and the son, we can set up a system of equations based on the given information.
Let's denote the current age of the father as "F" and the current age of the son as "S".
According to the given information:
"Before 5 years, a man was 3 years times his boy" can be written as:
F - 5 = 3(S - 5) ----(1)
"After 10 years, the father's age will be 6 more than 2 times his boy" can be written as:
F + 10 = 2(S + 10) + 6 ----(2)
Now, we can solve these equations to find the values of F and S.
Let's start by solving equation (1):
Expanding the equation:
F - 5 = 3S - 15
Moving the constant terms to the right side:
F = 3S - 15 + 5
F = 3S - 10 ----(3)
Next, substitute equation (3) into equation (2):
3S - 10 + 10 = 2(S + 10) + 6
Simplifying the equation:
3S = 2S + 20 + 6
3S = 2S + 26
Moving the constant term to the right side:
3S - 2S = 26
S = 26
Now that we know the son's age is 26, substitute this value back into equation (3):
F = 3(26) - 10
F = 78 - 10
F = 68
Therefore, the father is 68 years old and the son is 26 years old.