15.2% by mass solution of h2o2, density is 1.01g/ml then find the molarity of the sulution.
To find the molarity of the solution, we need to know the formula weight of H2O2 and the mass of H2O2 in the solution.
The formula weight of H2O2 is:
2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol
Now, to calculate the mass of H2O2 in the solution, we need to consider that the solution is 15.2% by mass H2O2. This means that for every 100 g of solution, there are 15.2 g of H2O2.
Let's assume we have 100 g of solution.
The mass of H2O2 in 100 g of solution is:
(15.2 g / 100 g) * 100 g = 15.2 g
The number of moles of H2O2 can be calculated using the formula:
moles = mass / formula weight
moles of H2O2 = 15.2 g / 34.02 g/mol = 0.447 mol
The volume of the solution can be calculated using the density:
volume = mass / density = 100 g / 1.01 g/mL = 99.01 mL
Finally, we can calculate the molarity (M) of the solution using the formula:
Molarity = moles / volume (in liters)
Molarity = 0.447 mol / 0.09901 L = 4.52 M
Therefore, the molarity of the solution is 4.52 M.
To find the molarity of the solution, we need to determine the number of moles of solute (H2O2) present in one liter of the solution.
First, let's calculate the mass of H2O2 in one liter of the solution:
mass = volume × density
mass = 1000 ml × 1.01 g/ml
mass = 1010 g
Next, let's calculate the number of moles of H2O2:
moles = mass / molar mass
The molar mass of H2O2 (hydrogen peroxide) is 34.0147 g/mol.
moles = 1010 g / 34.0147 g/mol
moles ≈ 29.70 mol
Finally, let's calculate the molarity of the solution:
molarity = moles / volume (in liters)
Since the volume is 1 L, the molarity is:
molarity = 29.70 mol / 1 L
molarity ≈ 29.70 M
Therefore, the molarity of the solution is approximately 29.70 M.
molarity is moles of solute per liter
1L of solution has a mass of ... 1010 g
mass of H2O2 is ... 1010 * .152 g
divide H2O2 mass by H2O2 molar mass to find the molarity