posted by milo
19.4 g of butane (58.12 g/mol) undergoes combustion according to the following equation. What pressure of carbon dioxide in atm is produced at 309 K in a 1.15 L flask.
2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)
Balance the equation.
Convert g butane to mols.
Using the coefficients in the balanced equation, convert mols butane to mols CO2.
Use PV = nRT substitute and solve for P of CO2