Precal
posted by Lissa .
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t16t^2
projectile formula: s(t)=1/2gt^2+v+t+h
g=acceleration due to gravity. V= the initial velocity, h= initial height, t=time, and s(t)= height at given time t
d. Explain how the equation relates to gravity and the projectile formula?

Precal 
Steve
You made a typo. Assuming that gravity pulls downward, it should be
s(t)= 1/2 gt^2 + vt + h
(d) is poorly worded. The equation relates the motion to acceleration by gravity. It combines the initial conditions (v and h) with the influence of gravity.
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