Pre-cal

posted by .

A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2

projectile formula: s(t)=1/2gt^2+v+t+h
g=acceleration due to gravity. V= the initial velocity, h= initial height, t=time, and s(t)= height at given time t

d. Explain how the equation relates to gravity and the projectile formula?

  • Pre-cal -

    You made a typo. Assuming that gravity pulls downward, it should be

    s(t)= -1/2 gt^2 + vt + h

    (d) is poorly worded. The equation relates the motion to acceleration by gravity. It combines the initial conditions (v and h) with the influence of gravity.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time …
  2. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time …
  3. pre-calc

    Physics: a ball is thrown vertically upward with an initial velocity of 80 feet per second. the distance (in feet) of the ball from the ground after t seconds if s=80t-16tt^2 a) draw the illustration b) for what time interval is the …
  4. Math-

    A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2 a.) at what time will the ball strike the ground b.) for what …
  5. Pre-Calculus

    A ball is thrown vertically upward with an initial velocity of 64 feet per second. The distance(in feet) of the ball from the ground after t seconds is s=64t-16t. At what time will the ball strike the ground?
  6. Pre-Calc

    ball thrown vertically upward with an initial velocity of 80 ft per second. The distance s(in ft) of the ball from the ground after t seconds is s=80t-16t^2. a. draw the illustration. b. for what time interval is ball more than 96 …
  7. Calculus

    Use a(t)=-32 ft/second squared as the acceleration due to gravity. A ball is thrown vertically upward from the ground with an initial velocity of 56 feet per second. For how many seconds will the ball be going upward?
  8. College Algebra

    Flight of a Ball If a ball is thrown upward at 96 feet per second from the top of a building that is 100 feet high, the height of the ball can be modeled by S(t)=100 + 96t -16t^2 feet, where t is the number of seconds after the ball …
  9. Precalculos

    A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is S(t)=96t-16t^2. At what time t will the ball strike the ground?
  10. Calculus

    Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.) A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 68 feet per second. How high will the ball go?

More Similar Questions