A potter is shaping a bowl on a a potter’s wheel. The wheel rotaes at a constant angular speed. The frictional force between her hands and the clay is 2.50 N. How large is the torque she produces on the wheel if the diameter of the bowl is 14 cm.

huh?

F * r = 2.50 * .07 Nm

To find the torque produced by the potter, we need to use the formula:

Torque = r * F * sin(θ)

Where:
- Torque is the rotational force or moment of force.
- r is the distance from the axis of rotation to the point where the force is applied (in this case, the radius of the bowl).
- F is the force applied (the frictional force between the potter's hands and the clay).
- θ is the angle between the force vector and the lever arm (90 degrees in this case because the force is perpendicular to the lever arm).

First, we need to convert the diameter of the bowl to radius by dividing it by 2:

Radius (r) = 14 cm / 2 = 7 cm = 0.07 m

Next, we substitute the values into the formula:

Torque = 0.07 m * 2.50 N * sin(90°)

τ = F*r = 15N*(0.13/2) = 0.975N-m