# As Physics

posted by cake

Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or â€œglidersâ€ are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a â€œperfectly elasticâ€ collision?
B) Calculate the velocity of the glider combination immediately after the collision.

6 marks

its 0.25 x 0.2+ 0.3 x 0 = (0.25+0.3)V as one of the trolley is 0.3kg so am i right?

bef=0.05
aft=0.55v
so 0.05=0.55v
0.05/0.55= 0.0909..

am i right

1. Damon

If they stick together the collision is NOT perfectly elastic. Energy is lost as heat.

You did the velocity stuck together correctly.

If it were perfectly elastic then it is a whole different ball game.

momentum before = momentum after
0.05 = .25 V2 + .3 V1
enerrgy before = energy after
(1/2)(.25)(.2^2) = (1/2).25 V2^2 + (1/2).3 V1^2

2. cake

so it is elastic collision, the momentum before and after is same and i dont think you need tow ok out energy

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