Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or “gliders� are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a “perfectly elastic� collision?
B) Calculate the velocity of the glider combination immediately after the collision.
6 marks
please help with B
its 0.25 x 0.2+ 0.3 x 0 = (0.25+0.3)V as one of the trolley is 0.3kg so am i right?
bef=0.05
aft=0.55v
so 0.05=0.55v
0.05/0.55= 0.0909..
am i right
If they stick together the collision is NOT perfectly elastic. Energy is lost as heat.
You did the velocity stuck together correctly.
If it were perfectly elastic then it is a whole different ball game.
momentum before = momentum after
0.05 = .25 V2 + .3 V1
enerrgy before = energy after
(1/2)(.25)(.2^2) = (1/2).25 V2^2 + (1/2).3 V1^2
so it is elastic collision, the momentum before and after is same and i dont think you need tow ok out energy
To calculate the velocity of the glider combination immediately after the collision, you are on the right track.
Since the collision is assumed to be perfectly elastic, momentum is conserved. Therefore, you can use the equation P = mv, where P is the momentum, m is the mass, and v is the velocity.
Let's denote the velocity of the glider combination after the collision as V.
The initial momentum of the first glider is 0 (as it is stationary), and the initial momentum of the second glider is given by P = 0.25 kg * 0.2 m/s = 0.05 kg m/s.
After the collision, the gliders stick together, so their masses combine to become 0.25 kg + 0.3 kg = 0.55 kg.
Using the equation P = mv for the combined gliders after the collision, we have:
0.05 kg m/s = 0.55 kg * V
To solve for V, divide both sides of the equation by 0.55 kg:
V = 0.05 kg m/s / 0.55 kg
V ≈ 0.0909 m/s
So the velocity of the glider combination immediately after the collision is approximately 0.0909 m/s.